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6m^2-42=0
a = 6; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·6·(-42)
Δ = 1008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1008}=\sqrt{144*7}=\sqrt{144}*\sqrt{7}=12\sqrt{7}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{7}}{2*6}=\frac{0-12\sqrt{7}}{12} =-\frac{12\sqrt{7}}{12} =-\sqrt{7} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{7}}{2*6}=\frac{0+12\sqrt{7}}{12} =\frac{12\sqrt{7}}{12} =\sqrt{7} $
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